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x/2-x/3+1=1/6(x+6)
We move all terms to the left:
x/2-x/3+1-(1/6(x+6))=0
Domain of the equation: 6(x+6))!=0We calculate fractions
x∈R
(-72x^2)/216x+108x^2/216x+()/216x+1=0
We multiply all the terms by the denominator
(-72x^2)+108x^2+1*216x+()=0
We add all the numbers together, and all the variables
108x^2+(-72x^2)+1*216x=0
Wy multiply elements
108x^2+(-72x^2)+216x=0
We get rid of parentheses
108x^2-72x^2+216x=0
We add all the numbers together, and all the variables
36x^2+216x=0
a = 36; b = 216; c = 0;
Δ = b2-4ac
Δ = 2162-4·36·0
Δ = 46656
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{46656}=216$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(216)-216}{2*36}=\frac{-432}{72} =-6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(216)+216}{2*36}=\frac{0}{72} =0 $
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