x/2=1+(x-20)/5

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Solution for x/2=1+(x-20)/5 equation: 



x/2=1+(x-20)/5

We move all terms to the left:

x/2-(1+(x-20)/5)=0

We calculate fractions


5x^2/()+(-(1+(x-20)*2)/()=0



We calculate terms in parentheses: +(-(1+(x-20)*2)/(), so:

-(1+(x-20)*2)/(

We multiply all the terms by the denominator


-(1+(x-20)*2)



We calculate terms in parentheses: -(1+(x-20)*2), so:

1+(x-20)*2

determiningTheFunctionDomain
(x-20)*2+1

We multiply parentheses

2x-40+1

We add all the numbers together, and all the variables

2x-39

Back to the equation:

-(2x-39)



We get rid of parentheses

-2x+39

Back to the equation:

+(-2x+39)



We get rid of parentheses

5x^2/()-2x+39=0

We multiply all the terms by the denominator


5x^2-2x*()+39*()=0

We add all the numbers together, and all the variables

5x^2-2x*()=0

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