x/2=2+(x-25)/5

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Solution for x/2=2+(x-25)/5 equation: 



x/2=2+(x-25)/5

We move all terms to the left:

x/2-(2+(x-25)/5)=0

We calculate fractions


5x^2/()+(-(2+(x-25)*2)/()=0



We calculate terms in parentheses: +(-(2+(x-25)*2)/(), so:

-(2+(x-25)*2)/(

We multiply all the terms by the denominator


-(2+(x-25)*2)



We calculate terms in parentheses: -(2+(x-25)*2), so:

2+(x-25)*2

determiningTheFunctionDomain
(x-25)*2+2

We multiply parentheses

2x-50+2

We add all the numbers together, and all the variables

2x-48

Back to the equation:

-(2x-48)



We get rid of parentheses

-2x+48

Back to the equation:

+(-2x+48)



We get rid of parentheses

5x^2/()-2x+48=0

We multiply all the terms by the denominator


5x^2-2x*()+48*()=0

We add all the numbers together, and all the variables

5x^2-2x*()=0

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