x/2=3+(x-30)/5

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Solution for x/2=3+(x-30)/5 equation: 



x/2=3+(x-30)/5

We move all terms to the left:

x/2-(3+(x-30)/5)=0

We calculate fractions


5x^2/()+(-(3+(x-30)*2)/()=0



We calculate terms in parentheses: +(-(3+(x-30)*2)/(), so:

-(3+(x-30)*2)/(

We multiply all the terms by the denominator


-(3+(x-30)*2)



We calculate terms in parentheses: -(3+(x-30)*2), so:

3+(x-30)*2

determiningTheFunctionDomain
(x-30)*2+3

We multiply parentheses

2x-60+3

We add all the numbers together, and all the variables

2x-57

Back to the equation:

-(2x-57)



We get rid of parentheses

-2x+57

Back to the equation:

+(-2x+57)



We get rid of parentheses

5x^2/()-2x+57=0

We multiply all the terms by the denominator


5x^2-2x*()+57*()=0

We add all the numbers together, and all the variables

5x^2-2x*()=0

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