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x/2x+3=9x-11
We move all terms to the left:
x/2x+3-(9x-11)=0
Domain of the equation: 2x!=0We get rid of parentheses
x!=0/2
x!=0
x∈R
x/2x-9x+11+3=0
We multiply all the terms by the denominator
x-9x*2x+11*2x+3*2x=0
Wy multiply elements
-18x^2+x+22x+6x=0
We add all the numbers together, and all the variables
-18x^2+29x=0
a = -18; b = 29; c = 0;
Δ = b2-4ac
Δ = 292-4·(-18)·0
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{841}=29$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-29}{2*-18}=\frac{-58}{-36} =1+11/18 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+29}{2*-18}=\frac{0}{-36} =0 $
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