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x/2x+3x+4=44
We move all terms to the left:
x/2x+3x+4-(44)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
3x+x/2x-40=0
We multiply all the terms by the denominator
3x*2x+x-40*2x=0
We add all the numbers together, and all the variables
x+3x*2x-40*2x=0
Wy multiply elements
6x^2+x-80x=0
We add all the numbers together, and all the variables
6x^2-79x=0
a = 6; b = -79; c = 0;
Δ = b2-4ac
Δ = -792-4·6·0
Δ = 6241
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{6241}=79$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-79)-79}{2*6}=\frac{0}{12} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-79)+79}{2*6}=\frac{158}{12} =13+1/6 $
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