x/2x-5=(x+3)/2x-1

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Solution for x/2x-5=(x+3)/2x-1 equation: 


x in (-oo:+oo)

(x/2)*x-5 = x*((x+3)/2)-1 // - x*((x+3)/2)-1

(x/2)*x-(x*((x+3)/2))-5+1 = 0

(-1*x*(x+3))/2+(x^2)/2-5+1 = 0

(-1*x*(x+3))/2+(x^2)/2+(-5*2)/2+(1*2)/2 = 0

x^2-1*x*(x+3)-5*2+1*2 = 0

2-3*x-10 = 0

-3*x-8 = 0

(-3*x-8)/2 = 0

(-3*x-8)/2 = 0 // * 2

-3*x-8 = 0

-3*x-8 = 0 // + 8

-3*x = 8 // : -3

x = 8/(-3)

x = -8/3

x = -8/3

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