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x/3(4x+1)=1/2(24x+6)
We move all terms to the left:
x/3(4x+1)-(1/2(24x+6))=0
Domain of the equation: 3(4x+1)!=0
x∈R
Domain of the equation: 2(24x+6))!=0We calculate fractions
x∈R
(2x^22/(3(4x+1)*2(24x+6)))+(-3x4/(3(4x+1)*2(24x+6)))=0
We calculate terms in parentheses: +(2x^22/(3(4x+1)*2(24x+6))), so:
2x^22/(3(4x+1)*2(24x+6))
We do not support expression: x^22
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