x/3(x+1)=2(x-1)

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Solution for x/3(x+1)=2(x-1) equation:



x/3(x+1)=2(x-1)
We move all terms to the left:
x/3(x+1)-(2(x-1))=0
Domain of the equation: 3(x+1)!=0
x∈R
We multiply all the terms by the denominator
x-((2(x-1)))*3(x+1)=0
We calculate terms in parentheses: -((2(x-1)))*3(x+1), so:
(2(x-1)))*3(x+1
We calculate terms in parentheses: -((2(x-1)))*3(x+1), so:
(2(x-1)))*3(x+1
We calculate terms in parentheses: -((2(x-1)))*3(x+1), so:
(2(x-1)))*3(x+1
We calculate terms in parentheses: -((2(x-1)))*3(x+1), so:
(2(x-1)))*3(x+1
We calculate terms in parentheses: -((2(x-1)))*3(x+1), so:
(2(x-1)))*3(x+1
We calculate terms in parentheses: -((2(x-1)))*3(x+1), so:
(2(x-1)))*3(x+1
We calculate terms in parentheses: -((2(x-1)))*3(x+1), so:
(2(x-1)))*3(x+1
We calculate terms in parentheses: -((2(x-1)))*3(x+1), so:
(2(x-1)))*3(x+1
We calculate terms in parentheses: -((2(x-1)))*3(x+1), so:
(2(x-1)))*3(x+1
We calculate terms in parentheses: -((2(x-1)))*3(x+1), so:
(2(x-1)))*3(x+1
We calculate terms in parentheses: -((2(x-1)))*3(x+1), so:
(2(x-1)))*3(x+1
We calculate terms in parentheses: -((2(x-1)))*3(x+1), so:
(2(x-1)))*3(x+1
We calculate terms in parentheses: -((2(x-1)))*3(x+1), so:
(2(x-1)))*3(x+1
We calculate terms in parentheses: -((2(x-1)))*3(x+1), so:
(2(x-1)))*3(x+1
We calculate terms in parentheses: -((2(x-1)))*3(x+1), so:
(2(x-1)))*3(x+1
We calculate terms in parentheses: -((2(x-1)))*3(x+1), so:
(2(x-1)))*3(x+1
We calculate terms in parentheses: -((2(x-1)))*3(x+1), so:
(2(x-1)))*3(x+1
We calculate terms in parentheses: -((2(x-1)))*3(x+1), so:
(2(x-1)))*3(x+1
We calculate terms in parentheses: -((2(x-1)))*3(x+1), so:
(2(x-1)))*3(x+1
We calculate terms in parentheses: -((2(x-1)))*3(x+1), so:
(2(x-1)))*3(x+1
We calculate terms in parentheses: -((2(x-1)))*3(x+1), so:
(2(x-1)))*3(x+1
We calculate terms in parentheses: -((2(x-1)))*3(x+1), so:
(2(x-1)))*3(x+1
We calculate terms in parentheses: -((2(x-1)))*3(x+1), so:
(2(x-1)))*3(x+1
We calculate terms in parentheses: -((2(x-1)))*3(x+1), so:
(2(x-1)))*3(x+1
We calculate terms in parentheses: -((2(x-1)))*3(x+1), so:
(2(x-1)))*3(x+1
We calculate terms in parentheses: -((2(x-1)))*3(x+1), so:
(2(x-1)))*3(x+1
We calculate terms in parentheses: -((2(x-1)))*3(x+1), so:
(2(x-1)))*3(x+1
We calculate terms in parentheses: -((2(x-1)))*3(x+1), so:
(2(x-1)))*3(x+1
We calculate terms in parentheses: -((2(x-1)))*3(x+1), so:
(2(x-1)))*3(x+1
We calculate terms in parentheses: -((2(x-1)))*3(x+1), so:
(2(x-1)))*3(x+1
We calculate terms in parentheses: -((2(x-1)))*3(x+1), so:
(2(x-1)))*3(x+1
We calculate terms in parentheses: -((2(x-1)))*3(x+1), so:
(2(x-1)))*3(x+1
We calculate terms in parentheses: -((2(x-1)))*3(x+1), so:
(2(x-1)))*3(x+1
We calculate terms in parentheses: -((2(x-1)))*3(x+1), so:
(2(x-1)))*3(x+1
We calculate terms in parentheses: -((2(x-1)))*3(x+1), so:
(2(x-1)))*3(x+1
We calculate terms in parentheses: -((2(x-1)))*3(x+1), so:
(2(x-1)))*3(x+1
We calculate terms in parentheses: -((2(x-1)))*3(x+1), so:
(2(x-1)))*3(x+1
We calculate terms in parentheses: -((2(x-1)))*3(x+1), so:
(2(x-1)))*3(x+1
We calculate terms in parentheses: -((2(x-1)))*3(x+1), so:
(2(x-1)))*3(x+1
We calculate terms in parentheses: -((2(x-1)))*3(x+1), so:
(2(x-1)))*3(x+1
We calculate terms in parentheses: -((2(x-1)))*3(x+1), so:
(2(x-1)))*3(x+1
We calculate terms in parentheses: -((2(x-1)))*3(x+1), so:
(2(x-1)))*3(x+1
We calculate terms in parentheses: -((2(x-1)))*3(x+1), so:
(2(x-1)))*3(x+1
We calculate terms in parentheses: -((2(x-1)))*3(x+1), so:
(2(x-1)))*3(x+1

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