x/3(x-5)=x+21

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Solution for x/3(x-5)=x+21 equation:



x/3(x-5)=x+21
We move all terms to the left:
x/3(x-5)-(x+21)=0
Domain of the equation: 3(x-5)!=0
x∈R
We get rid of parentheses
x/3(x-5)-x-21=0
We multiply all the terms by the denominator
x-x*3(x-5)-21*3(x-5)=0
Wy multiply elements
-3x^2(x-63x(x+x=0

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