x/3+3/5=-(1/2)

Solution for x/3+3/5=-(1/2) equation:

x/3+3/5=-(1/2)

We move all terms to the left:

x/3+3/5-(-(1/2))=0

We add all the numbers together, and all the variables

x/3+3/5-(-(+1/2))=0

We calculate fractions


20x^2/()+()/()+()/()=0

We add all the numbers together, and all the variables

20x^2/()+2=0

We multiply all the terms by the denominator


20x^2+2*()=0

We add all the numbers together, and all the variables

20x^2=0

a = 20; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·20·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{40}=0$