If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x in (-oo:+oo)
x/3-(x/12) = x/4-(1/3) // - x/4-(1/3)
x/3-(x/12)-(x/4)+1/3 = 0
1/3 = 0
x belongs to the empty set
x belongs to the empty set
| r/2+2r=7 | | 28=-12-2x | | 12/x+3=2x | | x*x+9x-36=0 | | n/14=10 | | 3/5y+1/2=7/2 | | 15x-9x^2=4 | | 4x-8=4(x+7) | | J/2=3j+2.3 | | -16t*t-8t+120=0 | | 2.5x=3/15 | | 6x=11-5x | | 2x+1=2(x-1)+3 | | 5x-9x^2=4 | | -w^2+5w-3=0 | | x*x+4x-32=0 | | 4x+7/x+1=x+3 | | 10975=x^2+20x+50 | | (-8x^2y^8z^-5)/(12x^4y^-7z^7) | | (x^2-5x+6)/(x^2-7x+6)*(x^2+x-42)/(21-4x-x^2) | | 0.16(y-5)+0.10y=0.20y-0.01(50) | | -12=15+x | | -(2m-4)=3m+24 | | 8=m/8 | | 5p+8=14+4p | | 15m-16m-15=0 | | -2(2i-3)=.5(6i+6) | | 5x+15y=90 | | 6x^2+72x-120=0 | | 261-6x=39x+16 | | 14x-122=4x-12 | | -2(-2i-3)=.5(6i+6) |