x/3=(2x+3)/7

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Solution for x/3=(2x+3)/7 equation: 



x/3=(2x+3)/7

We move all terms to the left:

x/3-((2x+3)/7)=0

We calculate fractions


7x^2/()+(-((2x+3)*3)/()=0



We calculate terms in parentheses: +(-((2x+3)*3)/(), so:

-((2x+3)*3)/(

We multiply all the terms by the denominator


-((2x+3)*3)



We calculate terms in parentheses: -((2x+3)*3), so:

(2x+3)*3

We multiply parentheses

6x+9

Back to the equation:

-(6x+9)



We get rid of parentheses

-6x-9

Back to the equation:

+(-6x-9)



We get rid of parentheses

7x^2/()-6x-9=0

We multiply all the terms by the denominator


7x^2-6x*()-9*()=0

We add all the numbers together, and all the variables

7x^2-6x*()=0

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