x/3=7x/12x-15

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Solution for x/3=7x/12x-15 equation:



x/3=7x/12x-15
We move all terms to the left:
x/3-(7x/12x-15)=0
Domain of the equation: 12x-15)!=0
x∈R
We get rid of parentheses
x/3-7x/12x+15=0
We calculate fractions
12x^2/36x+(-21x)/36x+15=0
We multiply all the terms by the denominator
12x^2+(-21x)+15*36x=0
Wy multiply elements
12x^2+(-21x)+540x=0
We get rid of parentheses
12x^2-21x+540x=0
We add all the numbers together, and all the variables
12x^2+519x=0
a = 12; b = 519; c = 0;
Δ = b2-4ac
Δ = 5192-4·12·0
Δ = 269361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{269361}=519$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(519)-519}{2*12}=\frac{-1038}{24} =-43+1/4 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(519)+519}{2*12}=\frac{0}{24} =0 $

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