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x/3x+4=16
We move all terms to the left:
x/3x+4-(16)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
x/3x-12=0
We multiply all the terms by the denominator
x-12*3x=0
Wy multiply elements
x-36x=0
We add all the numbers together, and all the variables
-35x=0
x=0/-35
x=0
Równanie nie ma rozwiązania
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