x/4+(3x-4)=22

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Solution for x/4+(3x-4)=22 equation: 



x/4+(3x-4)=22

We move all terms to the left:

x/4+(3x-4)-(22)=0

We get rid of parentheses

x/4+3x-4-22=0

We multiply all the terms by the denominator


x+3x*4-4*4-22*4=0

We add all the numbers together, and all the variables

x+3x*4-104=0

Wy multiply elements

x+12x-104=0

We add all the numbers together, and all the variables

13x-104=0

We move all terms containing x to the left, all other terms to the right

13x=104

x=104/13

x=8

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