x/4+x/6=1/2(x+3)

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Solution for x/4+x/6=1/2(x+3) equation: 



x/4+x/6=1/2(x+3)

We move all terms to the left:

x/4+x/6-(1/2(x+3))=0



Domain of the equation: 2(x+3))!=0

x∈R



We calculate fractions


24x^2/96x+16x^2/96x+()/96x=0

We multiply all the terms by the denominator


24x^2+16x^2+()=0

We add all the numbers together, and all the variables

40x^2=0

a = 40; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·40·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{80}=0$

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