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x/4-2x/x+2=1
We move all terms to the left:
x/4-2x/x+2-(1)=0
Domain of the equation: x!=0We add all the numbers together, and all the variables
x∈R
x/4-2x/x+1=0
We calculate fractions
x^2/4x+(-8x)/4x+1=0
We multiply all the terms by the denominator
x^2+(-8x)+1*4x=0
Wy multiply elements
x^2+(-8x)+4x=0
We get rid of parentheses
x^2-8x+4x=0
We add all the numbers together, and all the variables
x^2-4x=0
a = 1; b = -4; c = 0;
Δ = b2-4ac
Δ = -42-4·1·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16}=4$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4}{2*1}=\frac{0}{2} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4}{2*1}=\frac{8}{2} =4 $
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