x/4=(-2/3x)+50

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Solution for x/4=(-2/3x)+50 equation: 



x/4=(-2/3x)+50

We move all terms to the left:

x/4-((-2/3x)+50)=0



Domain of the equation: 3x)+50)!=0

x!=0/1

x!=0

x∈R



We calculate fractions


3x^2/12x+()/12x=0

We multiply all the terms by the denominator


3x^2+()=0

We add all the numbers together, and all the variables

3x^2=0

a = 3; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·3·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{6}=0$

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