x/4=(x-3)/7

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Solution for x/4=(x-3)/7 equation: 



x/4=(x-3)/7

We move all terms to the left:

x/4-((x-3)/7)=0

We calculate fractions


7x^2/()+(-((x-3)*4)/()=0



We calculate terms in parentheses: +(-((x-3)*4)/(), so:

-((x-3)*4)/(

We multiply all the terms by the denominator


-((x-3)*4)



We calculate terms in parentheses: -((x-3)*4), so:

(x-3)*4

We multiply parentheses

4x-12

Back to the equation:

-(4x-12)



We get rid of parentheses

-4x+12

Back to the equation:

+(-4x+12)



We get rid of parentheses

7x^2/()-4x+12=0

We multiply all the terms by the denominator


7x^2-4x*()+12*()=0

We add all the numbers together, and all the variables

7x^2-4x*()=0

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