x/4=(x-5)/5

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Solution for x/4=(x-5)/5 equation: 



x/4=(x-5)/5

We move all terms to the left:

x/4-((x-5)/5)=0

We calculate fractions


5x^2/()+(-((x-5)*4)/()=0



We calculate terms in parentheses: +(-((x-5)*4)/(), so:

-((x-5)*4)/(

We multiply all the terms by the denominator


-((x-5)*4)



We calculate terms in parentheses: -((x-5)*4), so:

(x-5)*4

We multiply parentheses

4x-20

Back to the equation:

-(4x-20)



We get rid of parentheses

-4x+20

Back to the equation:

+(-4x+20)



We get rid of parentheses

5x^2/()-4x+20=0

We multiply all the terms by the denominator


5x^2-4x*()+20*()=0

We add all the numbers together, and all the variables

5x^2-4x*()=0

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