x/4=2+(x-3)/3

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Solution for x/4=2+(x-3)/3 equation: 



x/4=2+(x-3)/3

We move all terms to the left:

x/4-(2+(x-3)/3)=0

We calculate fractions


3x^2/()+(-(2+(x-3)*4)/()=0



We calculate terms in parentheses: +(-(2+(x-3)*4)/(), so:

-(2+(x-3)*4)/(

We multiply all the terms by the denominator


-(2+(x-3)*4)



We calculate terms in parentheses: -(2+(x-3)*4), so:

2+(x-3)*4

determiningTheFunctionDomain
(x-3)*4+2

We multiply parentheses

4x-12+2

We add all the numbers together, and all the variables

4x-10

Back to the equation:

-(4x-10)



We get rid of parentheses

-4x+10

Back to the equation:

+(-4x+10)



We get rid of parentheses

3x^2/()-4x+10=0

We multiply all the terms by the denominator


3x^2-4x*()+10*()=0

We add all the numbers together, and all the variables

3x^2-4x*()=0

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