x/4=2x(x-3)/3

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Solution for x/4=2x(x-3)/3 equation: 



x/4=2x(x-3)/3

We move all terms to the left:

x/4-(2x(x-3)/3)=0

We calculate fractions


3x^2/()+(-(2x(x-3)*4)/()=0



We calculate terms in parentheses: +(-(2x(x-3)*4)/(), so:

-(2x(x-3)*4)/(

We multiply all the terms by the denominator


-(2x(x-3)*4)



We calculate terms in parentheses: -(2x(x-3)*4), so:

2x(x-3)*4

We multiply parentheses

8x^2-24x

Back to the equation:

-(8x^2-24x)



We get rid of parentheses

-8x^2+24x

Back to the equation:

+(-8x^2+24x)



We get rid of parentheses

3x^2/()-8x^2+24x=0

We multiply all the terms by the denominator


3x^2-8x^2*()+24x*()=0

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