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x/5(x+3)-2x=27
We move all terms to the left:
x/5(x+3)-2x-(27)=0
Domain of the equation: 5(x+3)!=0We add all the numbers together, and all the variables
x∈R
-2x+x/5(x+3)-27=0
We multiply all the terms by the denominator
-2x*5(x+3)+x-27*5(x+3)=0
We add all the numbers together, and all the variables
x-2x*5(x+3)-27*5(x+3)=0
Wy multiply elements
-10x^2(x-135x(x+x=0
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