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x/5(x-2)+3x=8(x+1)-3
We move all terms to the left:
x/5(x-2)+3x-(8(x+1)-3)=0
Domain of the equation: 5(x-2)!=0We add all the numbers together, and all the variables
x∈R
3x+x/5(x-2)-(8(x+1)-3)=0
We multiply all the terms by the denominator
3x*5(x-2)+x-((8(x+1)-3))*5(x-2)=0
We calculate terms in parentheses: -((8(x+1)-3))*5(x-2), so:We add all the numbers together, and all the variables
(8(x+1)-3))*5(x-2
x+3x*5(x-2)-((8(x+1)-3))*5(x-2)=0
Wy multiply elements
15x^2(x-((8(x+1)-3))*5(x-2)+x=0
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