x/5=(x+3)/2

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Solution for x/5=(x+3)/2 equation: 



x/5=(x+3)/2

We move all terms to the left:

x/5-((x+3)/2)=0

We calculate fractions


2x^2/()+(-((x+3)*5)/()=0



We calculate terms in parentheses: +(-((x+3)*5)/(), so:

-((x+3)*5)/(

We multiply all the terms by the denominator


-((x+3)*5)



We calculate terms in parentheses: -((x+3)*5), so:

(x+3)*5

We multiply parentheses

5x+15

Back to the equation:

-(5x+15)



We get rid of parentheses

-5x-15

Back to the equation:

+(-5x-15)



We get rid of parentheses

2x^2/()-5x-15=0

We multiply all the terms by the denominator


2x^2-5x*()-15*()=0

We add all the numbers together, and all the variables

2x^2-5x*()=0

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