x/5=x+6/x-2

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Solution for x/5=x+6/x-2 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

x/5 = x+6/x-2 // - x+6/x-2

x/5-x-(6/x)+2 = 0

x/5-x-6*x^-1+2 = 0

2*x^0-4/5*x^1-6*x^-1 = 0

(2*x^1-4/5*x^2-6*x^0)/(x^1) = 0 // * x^2

x^1*(2*x^1-4/5*x^2-6*x^0) = 0

x^1

(-4/5)*x^2+2*x-6 = 0

(-4/5)*x^2+2*x-6 = 0

DELTA = 2^2-(-6*4*(-4/5))

DELTA = -76/5

DELTA < 0

x in { } 

x belongs to the empty set

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