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x/5x+2(1-x)=2(2x-1)*
We move all terms to the left:
x/5x+2(1-x)-(2(2x-1)*)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
x/5x+2(-1x+1)-(2(2x-1)*)=0
We multiply parentheses
x/5x-2x-(2(2x-1)*)+2=0
We multiply all the terms by the denominator
x-2x*5x-((2(2x-1)*))*5x+2*5x=0
Wy multiply elements
-10x^2+x-((2(2x-1)*))*5x+10x=0
We add all the numbers together, and all the variables
-10x^2+11x-((2(2x-1)*))*5x=0
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