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x/5x^2=50
We move all terms to the left:
x/5x^2-(50)=0
Domain of the equation: 5x^2!=0We multiply all the terms by the denominator
x^2!=0/5
x^2!=√0
x!=0
x∈R
x-50*5x^2=0
Wy multiply elements
-250x^2+x=0
a = -250; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·(-250)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*-250}=\frac{-2}{-500} =1/250 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*-250}=\frac{0}{-500} =0 $
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