x/7(2x-3)=5

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Solution for x/7(2x-3)=5 equation: 


x in (-oo:+oo)

(x/7)*(2*x-3) = 5 // - 5

(x/7)*(2*x-3)-5 = 0

1/7*x*(2*x-3)-5 = 0

1/7*x*(2*x-3)-5 = 0

2/7*x^2-3/7*x-5 = 0

2/7*x^2-3/7*x-5 = 0

2/7*x^2-3/7*x-5 = 0

DELTA = (-3/7)^2-(-5*2/7*4)

DELTA = 289/49

DELTA > 0

x = ((289/49)^(1/2)+3/7)/(2/7*2) or x = (3/7-(289/49)^(1/2))/(2/7*2)

x = 5 or x = -7/2

(x+7/2)*(x-5) = 0

(x+7/2)*(x-5) = 0

( x+7/2 )

x+7/2 = 0 // - 7/2

x = -7/2

( x-5 )

x-5 = 0 // + 5

x = 5

x in { -7/2, 5 }

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