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x/8x+4=3x-6
We move all terms to the left:
x/8x+4-(3x-6)=0
Domain of the equation: 8x!=0We get rid of parentheses
x!=0/8
x!=0
x∈R
x/8x-3x+6+4=0
We multiply all the terms by the denominator
x-3x*8x+6*8x+4*8x=0
Wy multiply elements
-24x^2+x+48x+32x=0
We add all the numbers together, and all the variables
-24x^2+81x=0
a = -24; b = 81; c = 0;
Δ = b2-4ac
Δ = 812-4·(-24)·0
Δ = 6561
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{6561}=81$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(81)-81}{2*-24}=\frac{-162}{-48} =3+3/8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(81)+81}{2*-24}=\frac{0}{-48} =0 $
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