x/8x-(6x-3)=9

Solution for x/8x-(6x-3)=9 equation:

x/8x-(6x-3)=9

We move all terms to the left:

x/8x-(6x-3)-(9)=0


Domain of the equation: 8x!=0

x!=0/8

x!=0

x∈R


We get rid of parentheses

x/8x-6x+3-9=0

We multiply all the terms by the denominator


x-6x*8x+3*8x-9*8x=0

Wy multiply elements

-48x^2+x+24x-72x=0

We add all the numbers together, and all the variables

-48x^2-47x=0

a = -48; b = -47; c = 0;
Δ = b2-4ac
Δ = -472-4·(-48)·0
Δ = 2209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2209}=47$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-47)-47}{2*-48}=\frac{0}{-96}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-47)+47}{2*-48}=\frac{94}{-96}
=-47/48
$