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x/8x-12=6x
We move all terms to the left:
x/8x-12-(6x)=0
Domain of the equation: 8x!=0We add all the numbers together, and all the variables
x!=0/8
x!=0
x∈R
-6x+x/8x-12=0
We multiply all the terms by the denominator
-6x*8x+x-12*8x=0
We add all the numbers together, and all the variables
x-6x*8x-12*8x=0
Wy multiply elements
-48x^2+x-96x=0
We add all the numbers together, and all the variables
-48x^2-95x=0
a = -48; b = -95; c = 0;
Δ = b2-4ac
Δ = -952-4·(-48)·0
Δ = 9025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9025}=95$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-95)-95}{2*-48}=\frac{0}{-96} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-95)+95}{2*-48}=\frac{190}{-96} =-1+47/48 $
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