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x/9(x-5)=6x+30
We move all terms to the left:
x/9(x-5)-(6x+30)=0
Domain of the equation: 9(x-5)!=0We get rid of parentheses
x∈R
x/9(x-5)-6x-30=0
We multiply all the terms by the denominator
x-6x*9(x-5)-30*9(x-5)=0
Wy multiply elements
-54x^2(x-270x(x+x=0
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