x/9x2=18

Solution for x/9x2=18 equation:

x/9x^2=18

We move all terms to the left:

x/9x^2-(18)=0


Domain of the equation: 9x^2!=0

x^2!=0/9

x^2!=√0

x!=0

x∈R


We multiply all the terms by the denominator


x-18*9x^2=0

Wy multiply elements

-162x^2+x=0

a = -162; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·(-162)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*-162}=\frac{-2}{-324}
=1/162
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*-162}=\frac{0}{-324}
=0
$