x/x-2=x+5/x+1

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Solution for x/x-2=x+5/x+1 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

x/x-2 = x+5/x+1 // - x+5/x+1

x/x-x-(5/x)-2-1 = 0

x/x-x-5*x^-1-2-1 = 0

-1*x^1-5*x^-1-2*x^0 = 0

(-1*x^2-2*x^1-5*x^0)/(x^1) = 0 // * x^2

x^1*(-1*x^2-2*x^1-5*x^0) = 0

x^1

-x^2-2*x-5 = 0

-x^2-2*x-5 = 0

DELTA = (-2)^2-(-5*(-1)*4)

DELTA = -16

DELTA < 0

x in { } 

x belongs to the empty set

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