x/x2-25-x+3/x2-5x=-7/x2+5x

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Solution for x/x2-25-x+3/x2-5x=-7/x2+5x equation: 



x/x2-25-x+3/x2-5x=-7/x2+5x

We move all terms to the left:

x/x2-25-x+3/x2-5x-(-7/x2+5x)=0



Domain of the equation: x2!=0

x^2!=0/

x^2!=√0

x!=0

x∈R





Domain of the equation: x2+5x)!=0

x∈R



We add all the numbers together, and all the variables

x/x2-x+3/x2-5x-(+5x-7/x2)-25=0

We add all the numbers together, and all the variables

-6x+x/x2+3/x2-(+5x-7/x2)-25=0

We get rid of parentheses

-6x+x/x2+3/x2-5x+7/x2-25=0

We multiply all the terms by the denominator


-6x*x2+x-5x*x2-25*x2+3+7=0

We add all the numbers together, and all the variables

-25x^2+x-6x*x2-5x*x2+10=0

Wy multiply elements

-25x^2-6x^3-5x^3+x+10=0

We do not support expression: x^3

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