x1=-2,x2=-3

Solution for x1=-2,x2=-3 equation:

x1=-2.x^2=-3

We move all terms to the left:

x1-(-2.x^2)=0

We add all the numbers together, and all the variables

-(-2.x^2)+x=0

We get rid of parentheses

2.x^2+x=0

a = 2.; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·2.·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*2.}=\frac{-2}{4}
=-1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*2.}=\frac{0}{4}
=0
$