x2+(-45)x+350=0

Solution for x2+(-45)x+350=0 equation:

x2+(-45)x+350=0

We add all the numbers together, and all the variables

x^2+(-45)x+350=0

We multiply parentheses

x^2-45x+350=0

a = 1; b = -45; c = +350;
Δ = b2-4ac
Δ = -452-4·1·350
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45)-25}{2*1}=\frac{20}{2}
=10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45)+25}{2*1}=\frac{70}{2}
=35
$