x2+(23)x+3=0

Solution for x2+(23)x+3=0 equation:

x2+(23)x+3=0

We add all the numbers together, and all the variables

x^2+23x+3=0

a = 1; b = 23; c = +3;
Δ = b2-4ac
Δ = 232-4·1·3
Δ = 517
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-\sqrt{517}}{2*1}=\frac{-23-\sqrt{517}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+\sqrt{517}}{2*1}=\frac{-23+\sqrt{517}}{2}
$