x2+(7+x)2=10*2

Solution for x2+(7+x)2=10*2 equation:

x2+(7+x)2=10*2

We move all terms to the left:

x2+(7+x)2-(10*2)=0

We add all the numbers together, and all the variables

x2+(x+7)2-20=0

We add all the numbers together, and all the variables

x^2+(x+7)2-20=0

We multiply parentheses

x^2+2x+14-20=0

We add all the numbers together, and all the variables

x^2+2x-6=0

a = 1; b = 2; c = -6;
Δ = b2-4ac
Δ = 22-4·1·(-6)
Δ = 28
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{28}=\sqrt{4*7}=\sqrt{4}*\sqrt{7}=2\sqrt{7}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{7}}{2*1}=\frac{-2-2\sqrt{7}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{7}}{2*1}=\frac{-2+2\sqrt{7}}{2}
$