x2+(x+1)/3=x-8

Solution for x2+(x+1)/3=x-8 equation:

x2+(x+1)/3=x-8

We move all terms to the left:

x2+(x+1)/3-(x-8)=0

We add all the numbers together, and all the variables

x^2+(x+1)/3-(x-8)=0

We get rid of parentheses

x^2+(x+1)/3-x+8=0

We multiply all the terms by the denominator


x^2*3+(x+1)-x*3+8*3=0

We add all the numbers together, and all the variables

x^2*3+(x+1)-x*3+24=0

Wy multiply elements

3x^2+(x+1)-3x+24=0

We get rid of parentheses

3x^2+x-3x+1+24=0

We add all the numbers together, and all the variables

3x^2-2x+25=0

a = 3; b = -2; c = +25;
Δ = b2-4ac
Δ = -22-4·3·25
Δ = -296
Delta is less than zero, so there is no solution for the equation