x2+-11x+-32=-x

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Solution for x2+-11x+-32=-x equation:



x2+-11x+-32=-x
We move all terms to the left:
x2+-11x+-32-(-x)=0
We add all the numbers together, and all the variables
x2-11x-(-1x)-32++=0
We add all the numbers together, and all the variables
x^2-11x-(-1x)=0
We get rid of parentheses
x^2-11x+1x=0
We add all the numbers together, and all the variables
x^2-10x=0
a = 1; b = -10; c = 0;
Δ = b2-4ac
Δ = -102-4·1·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-10}{2*1}=\frac{0}{2} =0 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+10}{2*1}=\frac{20}{2} =10 $

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