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x2+0.058x-0.000144=0
We add all the numbers together, and all the variables
x^2+0.058x-0.000144=0
a = 1; b = 0.058; c = -0.000144;
Δ = b2-4ac
Δ = 0.0582-4·1·(-0.000144)
Δ = 0.00394
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.058)-\sqrt{0.00394}}{2*1}=\frac{-0.058-\sqrt{0.00394}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.058)+\sqrt{0.00394}}{2*1}=\frac{-0.058+\sqrt{0.00394}}{2} $
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