x2+03x-30=0

Solution for x2+03x-30=0 equation:

x2+03x-30=0

We add all the numbers together, and all the variables

x^2+03x-30=0

a = 1; b = 03; c = -30;
Δ = b2-4ac
Δ = 032-4·1·(-30)
Δ = 129
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(03)-\sqrt{129}}{2*1}=\frac{-3-\sqrt{129}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(03)+\sqrt{129}}{2*1}=\frac{-3+\sqrt{129}}{2}
$