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x2+1+9x-7+6x+2=180
We move all terms to the left:
x2+1+9x-7+6x+2-(180)=0
We add all the numbers together, and all the variables
x^2+15x-184=0
a = 1; b = 15; c = -184;
Δ = b2-4ac
Δ = 152-4·1·(-184)
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{961}=31$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-31}{2*1}=\frac{-46}{2} =-23 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+31}{2*1}=\frac{16}{2} =8 $
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