x2+1.732=2x2

Solution for x2+1.732=2x2 equation:

x2+1.732=2x^2

We move all terms to the left:

x2+1.732-(2x^2)=0

determiningTheFunctionDomain
-2x^2+x2+1.732=0

We add all the numbers together, and all the variables

-1x^2+1.732=0

a = -1; b = 0; c = +1.732;
Δ = b2-4ac
Δ = 02-4·(-1)·1.732
Δ = 6.928
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{6.928}}{2*-1}=\frac{0-\sqrt{6.928}}{-2}
=-\frac{\sqrt{}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{6.928}}{2*-1}=\frac{0+\sqrt{6.928}}{-2}
=\frac{\sqrt{}}{-2}
$