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x2+1.8x-0.1206=0
We add all the numbers together, and all the variables
x^2+1.8x-0.1206=0
a = 1; b = 1.8; c = -0.1206;
Δ = b2-4ac
Δ = 1.82-4·1·(-0.1206)
Δ = 3.7224
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.8)-\sqrt{3.7224}}{2*1}=\frac{-1.8-\sqrt{3.7224}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.8)+\sqrt{3.7224}}{2*1}=\frac{-1.8+\sqrt{3.7224}}{2} $
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