x2+10x+25=144

Solution for x2+10x+25=144 equation:

x2+10x+25=144

We move all terms to the left:

x2+10x+25-(144)=0

We add all the numbers together, and all the variables

x^2+10x-119=0

a = 1; b = 10; c = -119;
Δ = b2-4ac
Δ = 102-4·1·(-119)
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-24}{2*1}=\frac{-34}{2}
=-17
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+24}{2*1}=\frac{14}{2}
=7
$