x2+10x-3000=0

Solution for x2+10x-3000=0 equation:

x2+10x-3000=0

We add all the numbers together, and all the variables

x^2+10x-3000=0

a = 1; b = 10; c = -3000;
Δ = b2-4ac
Δ = 102-4·1·(-3000)
Δ = 12100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{12100}=110$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-110}{2*1}=\frac{-120}{2}
=-60
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+110}{2*1}=\frac{100}{2}
=50
$